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shebi
01-27-2011, 05:42 PM
THE GDB TOPIC IS "Construct a real world business problem and then apply simple linear regression analysis."



PLz reply quick




4M HAseeb

jannat noor
01-27-2011, 11:58 PM
Yar plzzzzzzzzzzzzzzzzzz
mth302 ki gdb share kro na

Xpert
01-28-2011, 03:21 AM
can you tell me the last date?

Arva Afrenish
01-28-2011, 12:35 PM
Construct a real world business problem and then apply simple linear regression analysis. its solution required as soon as posible. bz today is the last day for submitting it.smileys44:

Xpert
01-28-2011, 01:57 PM
X Y XY X2
100 70 7000 10000
200 70 14000 40000
400 80 32000 160000
500 100 5000 250000
å = 1200 å = 320 å =103000 å = 460000

Byx = nåXY – åXåY / nåX2 - (åX) 2

Byx = 4(103000)-((1200)(320)) / 4(460000)-(1200) 2

Byx = 0.07
ayx = y - Byx X

= ((åY/n) – ((0.07) (åX/n))

=(320/4) – (0.07)(1200/4)

= 59

y = 59 + 0.07 X is required regression equation.

Xpert
01-28-2011, 02:51 PM
another solution
Question:-
Suppose that 4 randomly chosen plots were treated with various level of fertilizer in the following yield of corn:-
Fertilizer(kg/Acre) X 100 200 400 500
Production(Bushels/Acre) Y 70 70 80 100
Estimate the Linear Regression of production Y on fertilizer X.
Solution:-
X Y XY X2
100 70 7000 10000
200 70 14000 40000
400 80 32000 160000
500 100 5000 250000
å = 1200 å = 320 å =103000 å = 460000
Byx = nåXY – åXåY / nåX2 - (åX) 2
Byx = 4(103000)-((1200)(320)) / 4(460000)-(1200) 2
Byx = 0.07
ayx = y - Byx X
= ((åY/n) – ((0.07) (åX/n))
=(320/4) – (0.07)(1200/4)
= 59
y = 59 + 0.07 X is required regression equation.