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1. ## STA301 Solution of the First Assignment solution Fall2010

(a)
Solution:

An array is a systematic arrangement of objects, usually in rows and columns
.

(b)
Make discrete frequency distribution from the given data,
1,2,3,2,1,2,1,3, 4,5,1,2,3,1,4,2, 2,3,2,1,4,4,4,2,1,

Also find;
• Cumulative frequencies
• Relative frequencies
Solution:

CLASS NO. Frequencies Cumulative frequency Relative frequency
1 7 7 0.28
2 8 7+8 = 15 0.32
3 4 15+4 =19 0.16
4 5 19+5 = 24 0.2
5 1 24+1 = 25 0.04
Total 25 ----

Question no.02

(a) Find Geometric mean from the following data.
1, 2, 3,2,4,5,4,3,4,-1,4, 3,0,1,-3, 2,4
Solution:

Geometric mean can not b calculated as there are some negative values and zero values present in the data.

(b) The weight of the 40 male students at a university is given in the following frequency table:
Weight frequency CF
118-126 3 3
127-135 5 3+5 =
136-144 9 8+9 =
145-153 12 17+12 =
154-162 5 29+5 =
163-171 4 34+4 =
172-180 2 38+2 = (equal to the sum of total frequency.. !

Calculate median and mode from the above data.

Solution:

MODE:

MEDIAN:

Where l=145, h=8, f=12, n/2=20 and c = 17

Put these values in formal and then calculate…

Question no.03

(b) For given data calculate range and coefficient of range,
0.035, 0.045, 0.031, 0.044, 0.032
Solution:
Xm=0.045
X0=0.031
Range: =

Coefficient of range: =
Put the values in the formula then calculate

(c) Calculate an appropriate measure of dispersion for the following data.

Farm Size (acre) No. of Farms
Bellow 40 394
41-80 461
81-120 391
121-160 334
161-200 169
201-240 113
241 and above 148

Solution:

Question solve with quartile deviation;;;

Quartile deviation = Q3 - Q1 / 2

With best regards

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2. in question no 2 (b)
why class boundaries not use

3. Solution can be found in the attachment. but its not free. YOu have to call me. for password. or pm me.

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## sta301 assignment 1

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