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Thread: Solution Assignment # 01(MTH 101) May 3,2010

  1. #1
    Senior Member viki's Avatar
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    Post Solution Assignment # 01(MTH 101) May 3,2010

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    Question # 1

    Solve the inequality

    Solution:
    multipling by 2 two both sides

    -10 < 4 - 3x < 4

    Subtracting 4 from both sides

    -14 < -3x < 0

    Divide -3 from both sides

    14 < x < 0
    3

    solution set is ( 0 , 14 / 3)


    Question # 2

    Show that (3,1), (6,3) and (2,9) are the vertices of a right triangle by using the Slopes form

    Solution:

    Given point= (x1,y1) = ( 3 , 1)
    = (x2,y2) = ( 6 , 3)
    = (x3, y3) = (2 , 9)

    Slop formula is m = y2 – y1
    x2 – x1

    perpendicular lines = m1m2 = -1

    then ,

    m1 = ( 3- 1) / ( 6 - 3) = 2 / 3
    m2 = ( 9 - 3) / (2 - 6) = 6 / - 4 = - 3 / 2
    m3 = ( 9 - 1) / (2 - 3) = -8


    m1 m2 = -1

    ( 2 / 3 ) ( -3 / 2 ) = -1

    -1 = -1

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  2. #2
    Senior Member Awais's Avatar
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    thankx for the solution...

  3. #3
    Junior Member
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    Thank u so much for ur help.

  4. #4
    Senior Member viki's Avatar
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    mention nt bahi u r welcome Always........

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