Solution Assignment # 01(MTH 101) May 3,2010

[viki]

View more random threads:

• Eng101 assignment no 1 spring 2015 complete solution
• MTH302 - Business Mathematics & Statistics Solution 11...
• ACC311 Fundamentals of Auditing Assigments N.02 Spring...
• ACC501 Business Finance Assignment No.2 Solution Spring...
• MCM511 Theories of Communication Assignments No. 1 Solution...
• CS502 Fundamentals of Algorithms Assignment No 3 Spring...
• CS302 Digital Logic and Design Assignment No. 03 Ideal...
• MGT502 Assignment 2 Idea Solution June 2010
• All Past Assignments with Solutions Of MGT402 Cost &...
• CS606 Compiler Construction Assignment 4 Solution July 2010

Question # 1

Solve the inequality

Solution:
multipling by 2 two both sides

-10 < 4 - 3x < 4

Subtracting 4 from both sides

-14 < -3x < 0

Divide -3 from both sides

14 < x < 0
3

solution set is ( 0 , 14 / 3)


Question # 2

Show that (3,1), (6,3) and (2,9) are the vertices of a right triangle by using the Slopes form

Solution:

Given point= (x1,y1) = ( 3 , 1)
= (x2,y2) = ( 6 , 3)
= (x3, y3) = (2 , 9)

Slop formula is m = y2 – y1
x2 – x1

perpendicular lines = m1m2 = -1

then ,

m1 = ( 3- 1) / ( 6 - 3) = 2 / 3
m2 = ( 9 - 3) / (2 - 6) = 6 / - 4 = - 3 / 2
m3 = ( 9 - 1) / (2 - 3) = -8


m1 m2 = -1

( 2 / 3 ) ( -3 / 2 ) = -1

-1 = -1

[Awais]

thankx for the solution...

Sponsored Links

[usmanshaikh]

Thank u so much for ur help.

[viki]

mention nt bahi u r welcome Always........