funtion of 1st qs is
f(x)= (3 if x greater then 3
4/9x+ 2/3 if x equal and less then 3
now solve yr 1st qs.....
in 3rd case limt x--->3 f(x) does not exist bcz criterion for the existence of limt is
limt x---->3 f(x) =L iff limt x---> c f(x) = limt x--->c- f(x) =limt x--->c+f(x) =L
so in third case L.H.L is not equal to R.H.L
therefore limt x---> 3 f(x) does not exist... ..
solution 1
ANSWER NO:1
• = 2
• = 3
• = Does not exist as limx→3+ f(x) ≠ limx→3- f(x)
• = 3
• = -∝
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