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Simplify the following Boolean expressions, using Boolean Algebraic rules:
ABC' + A'BC + ABC + A'BC'
= BC' (A+A')+BC' (A+A') //*Because A+A'=1
So,
=BC' (1)BC' (1)
=B(C'+C)=B(1)
=B
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(BC' + A'D) (AB'+ CD')
=BC'AB'+BC'CD'+A'DAB'+A'DCD'
=C'ABB'+BD'C'C+DB'AA'+A'CDD'
BY RULE A.A'=0
SO
BB'=0, CC'=0 , AA'=0 AND DD'=0
Answer =0
Question 2: [marks: 10]
Simplify the following Boolean functions, using Karnuagh maps:
F(A,B,C,D) = ∑ (3,7,11,13,14,15)
Solution:
Since the function has four variables so,a four variable map must be used.The minterms listed in the sum are marked by 1’s in the map.
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For Solution In Doc file see the attachment below
CS302Assignment2Solution.doc