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Thread: MTH302 GDB SOLUTION REQUIre

  1. #1

  2. #2
    Junior Member
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    Yar plzzzzzzzzzzzzzzzzzz
    mth302 ki gdb share kro na

  3. #3
    Administrator Xpert's Avatar
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    can you tell me the last date?

  4. #4

    Icon30 solution required of MTH 302 GDS

    Construct a real world business problem and then apply simple linear regression analysis. its solution required as soon as posible. bz today is the last day for submitting it.smileys44:

  5. #5
    Administrator Xpert's Avatar
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    X Y XY X2
    100 70 7000 10000
    200 70 14000 40000
    400 80 32000 160000
    500 100 5000 250000
    å = 1200 å = 320 å =103000 å = 460000

    Byx = nåXY – åXåY / nåX2 - (åX) 2

    Byx = 4(103000)-((1200)(320)) / 4(460000)-(1200) 2

    Byx = 0.07
    ayx = y - Byx X

    = ((åY/n) – ((0.07) (åX/n))

    =(320/4) – (0.07)(1200/4)

    = 59

    y = 59 + 0.07 X is required regression equation.

  6. #6
    Administrator Xpert's Avatar
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    another solution
    Question:-
    Suppose that 4 randomly chosen plots were treated with various level of fertilizer in the following yield of corn:-
    Fertilizer(kg/Acre) X 100 200 400 500
    Production(Bushels/Acre) Y 70 70 80 100
    Estimate the Linear Regression of production Y on fertilizer X.
    Solution:-
    X Y XY X2
    100 70 7000 10000
    200 70 14000 40000
    400 80 32000 160000
    500 100 5000 250000
    å = 1200 å = 320 å =103000 å = 460000
    Byx = nåXY – åXåY / nåX2 - (åX) 2
    Byx = 4(103000)-((1200)(320)) / 4(460000)-(1200) 2
    Byx = 0.07
    ayx = y - Byx X
    = ((åY/n) – ((0.07) (åX/n))
    =(320/4) – (0.07)(1200/4)
    = 59
    y = 59 + 0.07 X is required regression equation.

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