Yar plzzzzzzzzzzzzzzzzzz
mth302 ki gdb share kro na
THE GDB TOPIC IS "Construct a real world business problem and then apply simple linear regression analysis."View more random threads:
- MTH202 Assignment No 4 Solution soon fall January 2012
- MTH601 Operations Research assignment no 2 fall 7 January...
- Mkt501 Marketing Management VU current Assignment No. 2...
- hrm624 full and final solution april 2011
- Mgt611 Business & Labor Law Current Assignment No 2 Fall 21...
- MGMT611 Human Relations assignment no 2 fall January 2012
- ENG201 Business and Technical English Writing Assignment 1...
- psy101 assignment no 1 solution 2011
- MTH401 Assignment No 3 Solution Fall JANUARY 2012
- MGT411 GDB First 14.11.2011
PLz reply quick
4M HAseeb
Yar plzzzzzzzzzzzzzzzzzz
mth302 ki gdb share kro na
can you tell me the last date?
Urgent call: 03455242488. | Virtual University Assignments
Virtual University GDBs | Virtual University Papers | Vu Projects | Vu Handouts
About Expert
Construct a real world business problem and then apply simple linear regression analysis. its solution required as soon as posible. bz today is the last day for submitting it.smileys44:
X Y XY X2
100 70 7000 10000
200 70 14000 40000
400 80 32000 160000
500 100 5000 250000
å = 1200 å = 320 å =103000 å = 460000
Byx = nåXY – åXåY / nåX2 - (åX) 2
Byx = 4(103000)-((1200)(320)) / 4(460000)-(1200) 2
Byx = 0.07
ayx = y - Byx X
= ((åY/n) – ((0.07) (åX/n))
=(320/4) – (0.07)(1200/4)
= 59
y = 59 + 0.07 X is required regression equation.
Urgent call: 03455242488. | Virtual University Assignments
Virtual University GDBs | Virtual University Papers | Vu Projects | Vu Handouts
About Expert
another solution
Question:-
Suppose that 4 randomly chosen plots were treated with various level of fertilizer in the following yield of corn:-
Fertilizer(kg/Acre) X 100 200 400 500
Production(Bushels/Acre) Y 70 70 80 100
Estimate the Linear Regression of production Y on fertilizer X.
Solution:-
X Y XY X2
100 70 7000 10000
200 70 14000 40000
400 80 32000 160000
500 100 5000 250000
å = 1200 å = 320 å =103000 å = 460000
Byx = nåXY – åXåY / nåX2 - (åX) 2
Byx = 4(103000)-((1200)(320)) / 4(460000)-(1200) 2
Byx = 0.07
ayx = y - Byx X
= ((åY/n) – ((0.07) (åX/n))
=(320/4) – (0.07)(1200/4)
= 59
y = 59 + 0.07 X is required regression equation.
Sponsored Links
Urgent call: 03455242488. | Virtual University Assignments
Virtual University GDBs | Virtual University Papers | Vu Projects | Vu Handouts
About Expert
There are currently 1 users browsing this thread. (0 members and 1 guests)