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Thread: Mth101 first assignment spring 2011 solution

  1. #21
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    Xà-5 x^3+2x^2-15x


    =lim |x+5|
    xà-5 x(x+5)(x-3) X^3+2x^2-15


    NOW
    x+5 if x>-5
    |x+5|= -(x+5) if x<-5
    0 if x=-5
    Left Hand Limit

    Lim _ |x+5|
    xà-5 x(x+5)(x-3)

    =lim _ -(x+5)
    xà-5 x(x+5)(x-3)
    =lim _ -1
    xà-5 x(x-3)

    = -1 = -1
    -5(-5-3) -5(-8)

    = -1
    40
    Right Hand Side

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    Lim |x+5|
    xà-5^+ x(x+5)(x-3)

    =lim
    xà-5^+ x+5 = 1
    x(x+5)(x-3) 40
    NOW
    Left Hand Side # Right Hand Side
    LIMIT DOES NOT EXIST AT X= -5

  2. #22
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    U people need to concentrate a little to understand ...

  3. #23
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    please jaldi karian please

  4. #24
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    kia jaldi karna hai????? ek bonus day bhi hota hai janab.

  5. #25
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    Icon51 Mth101 assignmnt solution april 2011

    assignment on attachment
    Attached Files Attached Files

  6. #26
    sana.pari
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    Question # 2
    4x2+4y2+16y-4x=19
    4x2+4y2+2(-2)x+2(4y)-19=0
    g = -2
    f = +8 c = -19
    r = f 2 + g2 − c
    = (−2)2 + 82 − (−19)
    = 4 + 64 + 19
    = 87
    Radius = 87
    Center = (-2, 8)

    Question # 3
    x ≥ −2
    8 − x
    ⇒ x ≥ −2 ( 8 − x )
    ⇒ x ≥ −16 + 2 x
    ⇒ x − 2 x ≥ −16
    ⇒ − x ≥ −16
    ⇒ x ≤ 16
    ⇒ { x x ∈ R x ≤ 16}

  7. #27
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    plz upload it in word or pdf file it is very dificult to unerstand the words.

    plz today is last date of this assignment

  8. #28
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    oh ho. ok let me do something for you . i guess you still have a bonus day...

  9. #29
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    plz upload question NO.1
    plz hurry up

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