PROBLOM IN PROGRAMMING code 2011

[sana.pari]

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RESPECTED SIR THIS PROGRAM IS CODED IN OUR TEXT BOOK
SIR I HAD DONE THIS EXAMPLE AND TJIS EXAMPLE RUN SUCCESSFULLY
SIR ONE QUESTION RISES IN MINE MIND THAT WE HAVE DECLARED
THE SIZE OF ARRAY IS GIVEN AS 7 IT MEANS THAT ONLY SEVEN
VALUES CAN BE STORED BUT HERE WE HAD STORED ALL THE VALUES
OF THE NUMBERS GENERATED BY THE RAND FUNCTION

HOW DOES IT HAPPENED KINDLY TELL ME THAT WHAT DOES THIS
LOOP IS DOING
for (roll=1;roll<=600000;roll++)
frequency[1+rand()%6]++;
THE CODE IS SNIPPED THERE

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#include<iostream.h>
#include<conio.h>
#include<iomanip.h>
using std::setw;
#include<cstdlib>
using std::rand;
using std::srand;
#include<ctime>
using std::time;
main()
{
 int roll;
 int face;
 const int arraysize=7;
 int frequency[arraysize]={};
 for (roll=1;roll<=600000;roll++)
 frequency[1+rand()%6]++;
 cout<<"FACE";
 cout<<setw(13);
 cout<<"FREQUENCY";
 cout<<endl;
 for ( face=1;face<arraysize;face++)
 {
  cout<<setw(4);
  cout<<face;
  cout<<setw(13);
  cout<<frequency[face];
  cout<<endl;
}
cout<<getch();
}

[Support]

Dear Student,
This program is just like a game where a Die is rolled. We know that a Die consists of 6 numbers from 1 to 6 on its each different face. Here in this program, the objective is to find the number of times each face will come up when that die is rolled 600000 times. Let us look at the logic behind the loop which you are finding dificult to understand.

for (roll=1;roll<=600000;roll++) 
    frequency[1+rand()%6]++;

In the loop declaration, you can see that loop limit is less than equal to 600000, which means that this loop will be executed 600000 times. In other words, this limits describes the number of times the Die will be rolled. Now lets come to second statement of the above code. We know that a die can only have 6 faces. when the 1+rand()%6 is executed, it always returns a value less than or equal to 6 becuase this value will represent the value of each face of the die.