How to call by reference ? I have an error.

[sana.pari]

View more random threads:

• Function also provides encapsulation, what it means with an...
• what is difference b/w "cin" and "cout". plz...
• what is the function of ostream in c++ 2011
• What does hierarchy mean in concerned with Classes ?
• call by value, call by reference,call by pointer in data...
• can we define same functions for the two or more different...
• What is abstraction in c++ 2011?
• how we can store data into a file in C++ and java?
• Version Problem
• Create new variables with a loop? in c++ 2011 -12

Dear sir, Salaam, Kindly check my this code. I have an error. Please point out my mistake. I want to send the reference of variable x to the function square. bye. --------------------------------------------------------------------- #include using namespace std; void square(double); int main() { double x; x = 123.456; cout << "\n" << "In main(), before calling square(), x = " << x; square(&x); //Passing address of the variable x cout << "\n" << " In main(), after calling square(), x = " << x; } void square(double *x) //read as: x is a pointer of type double { *x = *x * *x; //Notice that there is no space in *x }

Sponsored Links

[Support]

Below is the correct modified code of your program. Compare this code with your previous code and try to point out your mistakes by yourself.

#include<iostream.h>

using namespace std;

void square(double *);

int main() 
{ 
    double x; 
    x = 123.456; 
    
    cout << "\n" << "In main(), before calling square(), x = " << x; 
    
    square(&x); 
    //Passing address of the variable x 
    
    cout << "\n" << " In main(), after calling square(), x = " << x; 
    
    
    system("pause");
}

void square(double *x) //read as: x is a pointer of type double 
{
     
    *x = *x * *x;

} //Notice that there is no space in *x