CS601 Data communication Assignment No 2 Solution Spring May 2014

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CS601 Data communication Assignment No 2 Solution Close Date May 29, 2014

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Assignment :
Question 1: (5 Marks)
Identify the TCP/IP layer against each of the protocols given in the
following table:
Protocols
TCP/IP Layers
ICMP
TCP
SMTP
UDP
IP
Question 2: (5 Marks)
In Dolphins, the audible range of frequencies is usually 1000 to 130,000
Hz. You have to calculate the bit rate of upper limit assuming 6 bits
per sample.
Question 3: (10 Marks)
You are required to represent the data stream 1010001110 using the
following encoding schemes on different graphs separately.
Manchester
Differential Manchester

[vuassignments]

In data transmission Manchester encoding is a method of transmitting bits that allows the receiver to easily synchronize with the sender. Manchester encoding splits each bit period into two, and ensures that there is always a transition between the signal levels in the middle of each bit. In Manchester encoding "1" is transmitted as 0 in the first half of the clock and 1 in the second half of the clock. And "0" is transmitted as 1 in the first half of the clock and 0 in the second half of the clock

[vuassignments]

Question 2: (5 Marks)
In Dolphins, the audible range of frequencies is usually 1000 to 130,000 Hz. You have to calculate the bit rate of upper limit assuming 6 bits per sample.
Solution:
No of bits per sample=6 bits/sample
Highest feq=130,000 HZ
According to nyquist theorem
Sampling rate=2(highest freq) samples/sec
Sampling rate=2(130,000)=260,000 samples/sec
Bit rate=sampling rate X No.of bits/sample
Bit rate=260,000 X 6 bits/sec
=156,000,0 bits/se