CS301‐ Data Structures Assignment No. 1 Solution Semester Spring 2013

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CS301‐ Data Structures Assignment No.1 Solution Semester Spring 2013 Due Date:22/04/2013

Assignment No.01

SEMESTER Spring 2013
CS301‐ Data Structures
Total Marks:20
Due Date:22/04/2013
Instructions
Please read the following instructions carefully before solving & submitting assignment: It should
be clear that your assignment will not get any credit (zero marks) if The assignment is submitted after due date.o The submitted code does NOT compile.o
The submitted assignment is other than.CPP file.The submitted assignment does NOT open or
file is corrupted.

o
The

assignment

is

copied

(from

other

student

or

ditto

copy

from

handouts

or

internet).

Uploading

instructions

For

clarity

and

simplicity,

You

are

required

to

Upload/Submit

only

ONE

.CPP

file.

Don’t

wait

for

grace

day.

Grace

day

is

only

given

if

there

is

problem

on

due

date.

Submit

your

solution

within

due

date.

Note

that

no

assignment

will

be

accepted

through

email

if

there

is

any

problem

on

grace

day


Note:

Use

ONLY

Dev
‐
C++

IDE.

Objective

The

objective

of

this

assignment

is


o
To

make

you

familiar

with

linked

list

data

structure

and

programming

techniques

to

implement

linked

list.



For

any

query

about

the

assignment,

contact

at

cs301@vu.edu.pk

GOOD

LUCK


Marks: 20
We know that in linked list we have one value and one
pointer (to hold the memory address of next node).
Note that it is not compulsory to have only one valu
e. There can be more than one value in one node but
pointer will remain one.
Write a C++ program to implement linked list data structur
e. In this problem every node should have six values,
the name of node and a pointer. Your program should prompt
the user to enter total nu
mber of nodes in the list.
After this give the name to node and save 6 different va
lues in node. Process should be
repeated for each node.
After entering values of all the nodes, sum the values in each node and sort the list in ascending order (on the
basis of sum calculated in each node) i.e. node with sma
llest sum comes first and node with largest sum comes
last.
Note
: Values within a single node
should not duplicate. If a user tries
to enter any duplic
ate value WITHIN A
NODE then show a warning message and ask user to enter value again.
The diagram given below is showing the sorted list.

Solution Guidelines:
1.
First understand the code given
in handouts about linked list.
2.
To save six different values in one node you can
use array as data member of Node class.
3.
Get the sum of six values and on comparison of sum of different
nodes sort the list.
4.
To get the idea about exac
t output of program, see Demo.wmv file
attached with assignment file.

Lectures

Covered:

This

assignment

covers

Lecture

#

1
‐
5

Deadline:

Your

assignment

must

be

uploaded

/

submitted

on

/

before,

April

22,

2013.

headNode
currentNode
lastCurrentNode
size = 5
9
8
7
6
5
4
9
8
7
6
5
3
9
8
7
6
5
2
9
8
7
6
5
9
2
7
6
1
5
1
XYZ
ABC
QRS
X12
DCB
Name of
Node
DCB
X12
QRS
ABC
XYZ
The list is shown (in ascending order) on the basis of sum of all values in node.

Sponsored Links

Assignment1_CS301.pdf

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Idea Solution

#include<iostream.h>
#include<cstdlib>
#include<conio.h>

using namespace std;

struct node
{

string data;
int Age;
struct node *next;
};

class queue
{



public:
node *rear;
node *frnt;

queue()
{
frnt=rear=NULL;
}
void insert();
void del();
void show();
void display();
void length();

};


void queue::insert()
{

string namec;
int agec;

node *temp = new node;
cout"\nHow many node you want to create? : ";
cin>>namec;
cout"\nEEnter the name of node : ";
cin>>agec;

temp->data = namec;
temp->Age=agec;
temp->next = NULL;
if(frnt == NULL){
frnt = temp;
}else{
rear->next = temp;
}
rear = temp;

}


void queue::show()
{
node *ptr1=frnt;
if(frnt==NULL)
{
cout"The Queue is empty!!\n";
return;
}
else
{
cout"\nCustomer at the front is : "ptr1->data "\n";

}
}

void queue::del()
{
if(frnt==NULL)
{
cout"\nSorry. Queue is empty";
return;
}
node *temp;
temp=frnt;
frnt=frnt->next;
cout"\nCustomer removed/served successfully : "temp->data ;
delete temp;

}


void queue::length()
{

int x;
x=0;
node *ptr1=frnt;
while(ptr1!=NULL)
{
ptr1=ptr1->next;
x++;
}
cout"\nTHe customers are : " x ;
}


void queue::display()
{
node *ptr1=frnt;
if(frnt==NULL)
{
cout"The Queue is empty!!";
return;
}
cout"\nThe Queue is\n";
cout "Name Age \n";

while(ptr1!=NULL)
{
cout ptr1-> data ptr1->Age "\n" ;
ptr1=ptr1->next;
}

}

int main()
{

queue q;
char choice;


while(1)
{
cout "\n1- for Enter/adding nodes in Queue";
cout "\n2- for Remove/serve a nodes";
cout "\n3- for Show nodes at front ";
cout "\n4- for Display all nodes in queue";
cout "\n5- for Show size of Queue ";
cout "\n6- for Exit";
cout "\n\nEnter your option: ";

cin>>choice;

switch(choice)
{
case '1':

char check;

do
{
q.insert();
cout"\n Do u want to enter another nodes(y/n): ";
cin>>check;
}
while(check=='y' || check=='Y');
break;
case '2':
q.del();
break;
case '3':
q.show();
break;
case '4':
q.display();
break;
case '5':
q.length();
break;
case '6':
exit(0);
break;

default:

cout"\n Sorry characters are no allowed. Please enter only option 1-6!!\n";
break;
}}

return 0;}