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STA301 Statistics and Probability Assignment No. 1 Solution and Discussion Fall 2014
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STA301 Statistics and Probability Assignment No. 1 Solution Ideas Date Dec 02, 2014


Question 1: (Marks: 5)




a) Construct a frequency distribution table where the class interval is 12, the number of classes is 6 and the smallest observation is 49 (lowest class limit). Also build the column of the relative frequency. The data is given below:

74, 49, 103, 95, 90, 118, 52, 88, 101, 96, 72, 56, 64, 110, 97, 59, 62, 96, 82, 65, 85, 105, 116, 91, 83, 99, 52, 76, 84, 90.

Question 2: (Marks: 5)

a) Compute the mean deviation from the mean for the following data.

(Where Mean = 3.949)


x
f
2.8
4
3.0
15
3.2
20
3.4
47
3.6
63
3.8
78
4.0
88
4.2
69
4.4
59
4.6
35
4.8
10
5.0
8
5.2
4
500
Question 3: (Marks: 3+2=5)



a) The ages of 22 football players are listed below:

66, 73, 68, 54, 25, 38, 67, 69, 74, 53, 52, 72, 55, 75, 37, 24, 13, 12, 11, 26, 39, 23

Make a stem and leaf display for the data.

b) Which variable (Discrete or Continuous) is more suitable in the following examples?

The content of a bottle of fluid is quoted as 1025 ml.
People are asked to state their age at their birthday.
People are asked to state how many times in the last month they visited their family doctor.
The height of trees at a nursery.
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#2
first of all arrange the data in ascending order.i.e.
49,52,52,56,59,62,64,65,72,74,76,82,83,84,85,88,90,90,91,95,96,96,97,99,101,103, 105,110, 116,118

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#3
its v easy tayyab follow the steps :

1)Arrange the list in ascending order like : 11,12,13,23.........

2)then take first common number out i mean to say take 1 as stem ..then take the numbers stating with 1

Stem: Leave:

1 1,2,3

es ma ye kia hy ka 11 ka 1 liya , 12 ka 2 liya aur 13 ka 3 liya wo leave ho gaey

aur 1 jo en sab ma common tha wo Stem hy ...

Hope u got it now

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#4
Question 2: (Marks: 5)

a) Compute the mean deviation from the mean for the following data.

(Where Mean = 3.949)

Formula which will be used for solution is :
Question 2: (Marks: 5)

a) Compute the mean deviation from the mean for the following data.

(Where Mean = 3.949)

Formula which will be used for solution is :
[ATTACH=CONFIG]24229[/ATTACH]


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